Team:Grenoble-EMSE-LSU/Project/Modelling/Building

From 2013.igem.org

(Difference between revisions)
Line 121: Line 121:
<p> which gives $Y=\frac{a}{bI_0+r}+Be{-(bI_0+r)t} $</p>
<p> which gives $Y=\frac{a}{bI_0+r}+Be{-(bI_0+r)t} $</p>
<br>
<br>
-
<p> $Y$ tends toward a steady state value, $\frac{a}{bI_0+r}$. Let's see how C </p>
+
<p> $Y$ tends toward a steady-state value, $\frac{a}{bI_0+r}$. Let's see how C evolves :</p>
<p>$\frac{dC}{dt}=C(r-kI_0Y)$</p>
<p>$\frac{dC}{dt}=C(r-kI_0Y)$</p>
<p>$\frac{dC}{dt}=C\left(r-\frac{kI_0a}{bI_0+r}+Be^{-(bI_0+r)t}\right)$</p>
<p>$\frac{dC}{dt}=C\left(r-\frac{kI_0a}{bI_0+r}+Be^{-(bI_0+r)t}\right)$</p>
-
<p> Thus, in the specific case where $I_0=\frac{r^2}{ak-rb}$, we have : $\lim_{t\to\infty}\frac{dC}{dt}(t)=0$</p>
+
<p> Thus, in the specific case that $I_0=\frac{r^2}{ak-rb}$, we have $\lim_{t\to\infty}\frac{dC}{dt}(t)=0$.</p>
<br>
<br>
<p> The resolution of this equation have shown the possibility to stabilize the system.</p>   
<p> The resolution of this equation have shown the possibility to stabilize the system.</p>   

Revision as of 22:52, 1 October 2013

Grenoble-EMSE-LSU, iGEM


Grenoble-EMSE-LSU, iGEM

Retrieved from "http://2013.igem.org/Team:Grenoble-EMSE-LSU/Project/Modelling/Building"