Team:Grenoble-EMSE-LSU/Project/Modelling/Building

From 2013.igem.org

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<h3> Third Model</h3>
<h3> Third Model</h3>
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<p> Until now, our equations describe the phototoxic effect of KillerRed as instantaneous : in the presence of light Killer Red produces ROS, which reacts immediately, killing or not the bacteria, and disappearing. It is however well known that cells can repair damages due to ROS, up to certain levels. We can thus consider that bacteria are unable to instantly repair all the damages caused by ROS, and with damages mounting up, they are more and more fragile and close to death. Considering this accumulation allows us to shift the effect of illumination, and so to have a more accurate model.</p>
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<p> Until now, our equations describe the phototoxic effect of KillerRed as instantaneous: in the presence of light Killer Red produces ROS, which immediately kills a certain proportion of the bacteria but has no lasting effect. It is well-known, however, that cells can repair damages due to ROS, up to a certain level. We can thus consider that bacteria are unable to instantly repair all the damages caused by ROS, and with damages mounting up, they are more and more fragile and close to death. Considering this accumulation allows us to shift the effect of illumination, and so to have a more accurate model.</p>
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<p> Written in its numeric form, the evolution of $C$ was described by : </p>
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<p> Written in its discrete-time form, the evolution of $C$ was described by </p>
<center style="font-size:150%;">
<center style="font-size:150%;">
$
$
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$
$
</center>
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<p> We now write : </p>
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<p> We now write </p>
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<center style="font-size:150%;">
$
$
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<p>
<p>
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The variable 'tox' is representative of the amount of damages inflicted to bacteria, and so of their probability to die. During a time step (for us, a minute), bacteria cures part of their injuries ($l<1$) and suffers new damages ($k'I(t)K(t)$). At first, few bacteria die : $\mbox{tox}(t)\cong k'I(t)K(t)$, then, 'tox' increases until it reach $\mbox{tox}(t)\cong\frac{k'}{1-l}I(t)K(t)$
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The variable 'tox' is representative of the amount of damages inflicted to bacteria, and so of their probability of dying. During a time step (for us, a minute), bacteria cures part of their injuries ($l<1$) and suffers new damages ($k'I(t)K(t)$). At first, few bacteria die : $\mbox{tox}(t)\cong k'I(t)K(t)$, then, 'tox' increases until it reach $\mbox{tox}(t)\cong\frac{k'}{1-l}I(t)K(t)$
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</p>
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<p> This new equation can also be written in analytical form :</p>
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<p> This new equation can also be written in continuous-time form:</p>
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<center style="font-size:150%;">
$
$
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$
$
</center>
</center>
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<p> But there is no analytical solution. We will therefore rely on numerical solutions in the following work.</p>
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<p> But there is no analytical solution for this equation. We will therefore rely on numerical solutions in what follows.</p>
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Revision as of 23:34, 1 October 2013

Grenoble-EMSE-LSU, iGEM


Grenoble-EMSE-LSU, iGEM

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