Team:USP-Brazil/Model:Stochastic

From 2013.igem.org

(Difference between revisions)
Line 36: Line 36:
-
When there are $[A]$ os molecules "trying" to react the first reaction will occur with a probability distribution (as we see on sections 5.4.1 and 5.7.3 in [1]) given by:
+
<p> When there are $[A]$ os molecules "trying" to react the first reaction will occur with a probability distribution (as we see on sections 5.4.1 and 5.7.3 in [1]) given by:</p>
  $$p(t) = [A] \lambda e^{- [A] \lambda t}$$
  $$p(t) = [A] \lambda e^{- [A] \lambda t}$$
-
 
+
<p>
We can see that this $\lambda$ parameter really looks like a parameter of a deterministic equation: $$\frac{d[A]}{dt} = - k_A [A]$$
We can see that this $\lambda$ parameter really looks like a parameter of a deterministic equation: $$\frac{d[A]}{dt} = - k_A [A]$$
 +
</p>
 +
<p>
Analising that the mean life time must be the same in both, to fit the same kind of experimental results, we realized that:
Analising that the mean life time must be the same in both, to fit the same kind of experimental results, we realized that:
 +
</p>
\begin{equation}
\begin{equation}
\lambda = k_A
\lambda = k_A
Line 52: Line 55:
X_f + et \rightleftharpoons X_et  
X_f + et \rightleftharpoons X_et  
\end{equation}
\end{equation}
-
 
+
<p>
The Probability of each reaction happens before a time <i>t<\i> follows the distribution:
The Probability of each reaction happens before a time <i>t<\i> follows the distribution:
-
 
+
</p>
\begin{equation}
\begin{equation}
Line 64: Line 67:
$$
$$
-
<p>As we explained before, the Rates $beta_ET$. is the same one from the Deterministic model.<\p>
+
<p>As we explained before, the Rates $beta_ET$. is the same one from the Deterministic model.</p>
 +
<p> ====AQUELA TABELA VAI POR AQUI===== </p>
 +
<p> If we have some reactions happening at the rate</p> $$p_i(t) = - a_i e^{-a_i t}$$
-
====AQUELA TABELA VAI POR AQUI=====
+
<p>Then the probability of a reaction occurring at a time previous to $t_A$ is: </p>
-
If we have some reactions happening at the rate $$p_i(t) = - a_i e^{-a_i t}$$
+
-
 
+
-
 
+
-
Then the probability of a reaction occurring at a time previous to $t_A$ is:
+
\begin{equation}
\begin{equation}
P_i(t \leq t_A)= \int_0^{t_A} p_i(t) = 1 - e^{-a_i t}   
P_i(t \leq t_A)= \int_0^{t_A} p_i(t) = 1 - e^{-a_i t}   
Line 76: Line 77:
-
 
+
<p>And the probability that the reaction does not occour before this time is:</p>
-
And the probability that the reaction does not occour before this time is:
+
$$P_i(t \geq t_A) = 1 - P(t \leq t_A)=  e^{-a_i t}  $$
$$P_i(t \geq t_A) = 1 - P(t \leq t_A)=  e^{-a_i t}  $$
-
 
+
<p>Being all the reactions independents, the probability of no reaction occurring before a given time point $t_* $is equal to the probability all reactions occurring before $t_A $. That is:</p>
-
 
+
-
Being all the reactions independents, the probability of no reaction occurring before a given time point $t_* $is equal to the probability all reactions occurring before $t_A $. That is:
+
$$ P_0(t \geq t_A) = \prod_{i=1}^{11}  P_i(t \geq t_A) = \prod_{i=1}^{11} e^{- a_i t_A} $$
$$ P_0(t \geq t_A) = \prod_{i=1}^{11}  P_i(t \geq t_A) = \prod_{i=1}^{11} e^{- a_i t_A} $$
-
 
+
<p>Defining </p>$$a_0 = \sum_{i=1}^{11} a_i $$
-
Defining $$a_0 = \sum_{i=1}^{11} a_i $$
+
<p>So we realize that the probability of one reaction occurring at a time before $t_A$ is</p>
-
So we realize that the probability of one reaction occurring at a time before $t_*$ is
+
$$ P_0(t \geq t_A) =  e^{a_0 t_A}$$
$$ P_0(t \geq t_A) =  e^{a_0 t_A}$$
-
And therefore the time until the first reaction will be given by the distribution:%which distribution is:
+
<p>And therefore the time until the first reaction will be given by the distribution:</p>
$$p(t) = - a_0 e^{a_0t}
$$p(t) = - a_0 e^{a_0t}
$$
$$
-
 
+
<p>
-
Through a parameter change, it is possible to calculate the distribution of the time interval between two reactions. Given a random variable $r$, uniformly distributed in $[0,1]$, the following quantity has a probability distribution of $  - a_0 e^{a_0t} $:
+
Through a parameter change, it is possible to calculate the distribution of the time interval between two reactions. Given a random variable $r$, uniformly distributed in $[0,1]$. The quantity </p>
$$ \Delta t = \frac{1}{a_0}\ln (1/r)$$
$$ \Delta t = \frac{1}{a_0}\ln (1/r)$$
-
 
+
has a probability distribution given by: $$  - a_0 e^{a_0t} $$
Once the the time $t + \Delta t$  when the next reaction occurs is calculated, all that remains is to choose which reaction should happen. Another random variable uniformly distributed in $[0,1]$ is used, and the probability correspondent to each reaction $i$ is $P_i = a_i/a_0 $.
Once the the time $t + \Delta t$  when the next reaction occurs is calculated, all that remains is to choose which reaction should happen. Another random variable uniformly distributed in $[0,1]$ is used, and the probability correspondent to each reaction $i$ is $P_i = a_i/a_0 $.
-
<h3>Guilespe<\h3>
+
<h3>Guilespe</h3>
This stochastic simulation was implemented by the Gillespie algorithm, described above and well explained in [2]. This algorithm consists in repeating the instructions below beginning at some initial condition for the metabolites, and updating the amount of each kind of mollecule after each time interval.
This stochastic simulation was implemented by the Gillespie algorithm, described above and well explained in [2]. This algorithm consists in repeating the instructions below beginning at some initial condition for the metabolites, and updating the amount of each kind of mollecule after each time interval.
-
 
+
\begin{itemize}
-
 
+
\item[•] Generate two random numbers $r_1, r_2$ uniformly distributed in $[0,1]$
-
 
+
\item[•] Compute the time when the next chemical reaction takes place as $t+\Delta t$
 +
where $$ \Delta t = \frac{1}{a_0}\ln (1/r)$$
 +
\item[•] Choose with reaction occurs using $r_2$ and giving each reaction $i$ a probabilty $P_i = a_i/a_0 $
 +
\item[•] Update the amount of molecules at time $t + \Delta t.$ according to the table above.
 +
\end{itemize}

Revision as of 02:32, 28 September 2013

Template:Https://2013.igem.org/Team:USP-Brazil/templateUP

Modelling

Stochastic model

Introduction

We want to simulate a cell where is happening all the chemical reactions discribed in the Deterministic Model as a Stochastical Process whose states are determinated by a collection of nine numbers:

\begin{equation} (et, met, X_f,X_{et}, X_{met}, P_f,P_{et}, P_{met}, R) \end{equation}

Those numbers represent the amount of mollecules of each chemical species in the cell. Respectively, the amount of ethanol, methanol, free transcription factor, ethanol-binded transcription factor, methanol-binded transcription factor, free promoter, ethanol-binded promoter, methanol-binded promoter and RFP molecules inside the cell.

Continuous Time Markov Chain

The main idea behind the Stochastic Modeling is that given an chemical reaction, e.g.: $$A \longrightarrow B$$ A single mollecule will react after some time $t$, following a probability distribution of the form $$p(t) = \lambda e^{-\lambda t}$$

These are the only kind of distribution in continuous time which do not have a "memory" or in Mathamatical language:

\begin{equation} P(X (t+\delta t) = i | X(t) = j) =P(X (\delta t) = i | X(0) = j) \end{equation}

So the probability does not depend of which states the system was in the time interval [0,t], that is, the future state of the system only depends on its present state.

A larger explanation of that is in Chapter 5 of [1].

When there are $[A]$ os molecules "trying" to react the first reaction will occur with a probability distribution (as we see on sections 5.4.1 and 5.7.3 in [1]) given by:

$$p(t) = [A] \lambda e^{- [A] \lambda t}$$

We can see that this $\lambda$ parameter really looks like a parameter of a deterministic equation: $$\frac{d[A]}{dt} = - k_A [A]$$

Analising that the mean life time must be the same in both, to fit the same kind of experimental results, we realized that:

\begin{equation} \lambda = k_A \end{equation}

Our Circuit by Markov

\begin{equation} X_f + et \rightleftharpoons X_et \end{equation}

The Probability of each reaction happens before a time t<\i> follows the distribution:

\begin{equation} P((et,Xf,Xet) \rightarrow (et-1,Xf-1,Xet+1),t)= { \beta_{et}^{+}[Xf][et]} e^{- \beta_{et}^{+}[Xf][et] t} \end{equation} $$ P((et,Xf,Xet) \rightarrow (et+1,Xf+1,Xet-1) ,t)= { \beta_{et}^{-}[Xet]}e^{- \beta_{et}^{-}[Xf][et] t} $$

As we explained before, the Rates $beta_ET$. is the same one from the Deterministic model.

====AQUELA TABELA VAI POR AQUI=====

If we have some reactions happening at the rate

$$p_i(t) = - a_i e^{-a_i t}$$

Then the probability of a reaction occurring at a time previous to $t_A$ is:

\begin{equation} P_i(t \leq t_A)= \int_0^{t_A} p_i(t) = 1 - e^{-a_i t} \end{equation}

And the probability that the reaction does not occour before this time is:

$$P_i(t \geq t_A) = 1 - P(t \leq t_A)= e^{-a_i t} $$

Being all the reactions independents, the probability of no reaction occurring before a given time point $t_* $is equal to the probability all reactions occurring before $t_A $. That is:

$$ P_0(t \geq t_A) = \prod_{i=1}^{11} P_i(t \geq t_A) = \prod_{i=1}^{11} e^{- a_i t_A} $$

Defining

$$a_0 = \sum_{i=1}^{11} a_i $$

So we realize that the probability of one reaction occurring at a time before $t_A$ is

$$ P_0(t \geq t_A) = e^{a_0 t_A}$$

And therefore the time until the first reaction will be given by the distribution:

$$p(t) = - a_0 e^{a_0t} $$

Through a parameter change, it is possible to calculate the distribution of the time interval between two reactions. Given a random variable $r$, uniformly distributed in $[0,1]$. The quantity

$$ \Delta t = \frac{1}{a_0}\ln (1/r)$$ has a probability distribution given by: $$ - a_0 e^{a_0t} $$ Once the the time $t + \Delta t$ when the next reaction occurs is calculated, all that remains is to choose which reaction should happen. Another random variable uniformly distributed in $[0,1]$ is used, and the probability correspondent to each reaction $i$ is $P_i = a_i/a_0 $.

Guilespe

This stochastic simulation was implemented by the Gillespie algorithm, described above and well explained in [2]. This algorithm consists in repeating the instructions below beginning at some initial condition for the metabolites, and updating the amount of each kind of mollecule after each time interval. \begin{itemize} \item[•] Generate two random numbers $r_1, r_2$ uniformly distributed in $[0,1]$ \item[•] Compute the time when the next chemical reaction takes place as $t+\Delta t$ where $$ \Delta t = \frac{1}{a_0}\ln (1/r)$$ \item[•] Choose with reaction occurs using $r_2$ and giving each reaction $i$ a probabilty $P_i = a_i/a_0 $ \item[•] Update the amount of molecules at time $t + \Delta t.$ according to the table above. \end{itemize} \begin{equation} \end{equation} \begin{equation} \end{equation} \begin{equation} \end{equation} \begin{equation} \end{equation}

References

[1] Sheldon M. Ross, Stochastic Process, Wiley, New York 1996

[2] Radek Erban, S. Jonathan Chapman, Philip K. Maini: A prac tical guide to stochastic simulations of reaction-diffusion processes , http://arxiv.org/abs/0704.1908

RFP Visibility | Deterministic Model | Stochastic Model

Template:Https://2013.igem.org/Team:USP-Brazil/templateDOWN