Team:Grenoble-EMSE-LSU/Project/Instrumentation

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<p>The value of the resistor is also:<img src="https://static.igem.org/mediawiki/2013/9/92/Eq_R_circuit.PNG" alt="Determination_of_R"/></br></br>
<p>The value of the resistor is also:<img src="https://static.igem.org/mediawiki/2013/9/92/Eq_R_circuit.PNG" alt="Determination_of_R"/></br></br>
In order for the resistor not to burn, the power dissipated due to the Joule effect need to be under 0.25W.</br>  
In order for the resistor not to burn, the power dissipated due to the Joule effect need to be under 0.25W.</br>  
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But it is not the case here! P=UI=RI²=1.4 x 0.5² = <strong><I>0.35W > 0.25W</I></strong></br>
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But it is not the case here!<img src="https://static.igem.org/mediawiki/2013/6/6d/Joule_effect.PNG" alt="Joule_effect"/></br>
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To solve this issue we use a little trick. We put two resistors in parallel that have 2xR=2.8 Ω</br>
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To solve this issue we use a little trick. We put two resistors in parallel that have <strong>2xR=2.8 Ω</strong></br>
So that we divide the power dissipated due to the Joule effect by two but keep the same intensity Ie.</br>
So that we divide the power dissipated due to the Joule effect by two but keep the same intensity Ie.</br>

Revision as of 00:00, 2 October 2013

Grenoble-EMSE-LSU, iGEM


Grenoble-EMSE-LSU, iGEM

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