Team:Grenoble-EMSE-LSU/Project/Instrumentation

From 2013.igem.org

(Difference between revisions)
Line 112: Line 112:
Since we cannot be sure that our alimentation is completely stable, we need to stabilize it thank to a bipolar transistor, three diodes and two resistors.</br></br>  
Since we cannot be sure that our alimentation is completely stable, we need to stabilize it thank to a bipolar transistor, three diodes and two resistors.</br></br>  
We know that:</br></br>
We know that:</br></br>
 +
In order for the resistor not to burn, the power dissipated due to the Joule effect need to be under 0.25W. But it is not the case here!  P=UI=RI^2=1.4 x 0.5² = 0.35W > 0.25W</br>
 +
To solve this issue we use a little trick. We put two resistors in parallel that have 2xR=2.8 Ω</br>
 +
So that we divide the power dissipated due to the Joule effect by two but keep the same intensity Ie.</br>
 +
</p>
</p>

Revision as of 23:05, 1 October 2013

Grenoble-EMSE-LSU, iGEM


Grenoble-EMSE-LSU, iGEM

Retrieved from "http://2013.igem.org/Team:Grenoble-EMSE-LSU/Project/Instrumentation"