"

From 2013.igem.org

Contents 1 Running the Model 1.1 Physical conditions: 1.2 Flux rate: 2 The Non-monooxygenase Pathway 2.1 Summary of the ODE: 2.2 Raw MATLAB code: 2.3 MATLAB output: 3 The Monooxygenase Pathway 3.1 ODE overview: 3.2 Raw MATLAB code: 3.3 MATLAB output:

Running the Model

The model was run using MATLAB through the ODE solver ODE45. The modelling for both the pathays had initial conditions of:

Constant	Value	Comment
KM A	0.530 mM	From literature [1]
kcat A	3.3 s-1	From literature [1]
KM B	0.940 mM	From literature [2]
kcat B	0.0871 s-1	From literature [2]
KM C	7.2 mM	From literature [3]
kcat c	89.8 s-1	From literature [3]
KM D	0.160 mM	From literature [4]
kcat D	0.600 s-1	From literature [4]
KM E	20 mM	From literature [5]
kcat E	25.4 s-1	From literature [5]
β, γ, δ & ε	0 mM	Not naturally present in cells.
αout	1 mM	Initial concentration of DCA in solution (arbitrary)
αin	0.001 mM	Initial concentration of DCA in cell
A, B, C, D, E	25.55 mM	Estimation from literature [11], as described in "principles".
	2 x 108 cells / mL	Initial cell concentration which allows appropriate growth

Physical conditions:

The model assumes that the cells are present in minimal media prior to DCA exposure and that the DCA is instantaneously and evenly present at time = 0 min in a solution of homogeneously mixed cells Many other assumptions have been made in the construction of the model and are outlined in the mathematical model section.

Flux rate:

By using the constants summarised in the previous section the flux, J, took the value (alongside the bacterial surface area, S):

The Non-monooxygenase Pathway

Summary of the ODE:

This system of ODE has been explained and justified in the previous section.

Raw MATLAB code:

function dy = nop450(t,y)
 
dy=zeros(7,1);
 
dy(1)= -y(7)*(6*10^(-12))*0.0463067*(y(1)-y(2));
dy(2)= ((6*10^(-12))*0.0463067*(y(1)-y(2)))-3.3*25.55*(y(2)/(0.53+y(2)));
dy(3)= 3.3*25.55*(y(2)/(0.53+y(2)))-0.0871*25.55*(y(3)/(0.94+y(3)));
dy(4)= .0871*25.55*(y(3)/(0.94+y(3)))- 0.6*25.55*(y(4)/(0.16+y(4)));
dy(5)= 0.6*25.55*(y(4)/(0.16+y(4))) - 25.4*25.55*(y(5)/(20+y(5)));
 
   if y(6) >  2*10^(-10)
      dy(6)= 25.4*25.55*(y(5)/(20+y(5))) -1.5789*10^(-10)
   else
       dy(6) = 25.4*25.55*(y(5)/(20+y(5)))
   end
   
   if y(6) > 0.0005 
        if y(7) > 1.6*10^11
            dy(7)=0
        else
            dy(7) = 5*10^6
        end
   else
        dy(7) = 0
   end
 
end

MATLAB output:

The rate at which DCA is removed in solution:

Graph 1: The blue line represents how the concentration of DCA in solution (extracellular) decreases due to the action of our DCA degraders. The red line represents the intracellular concentions of the metabolites (disregard in this graph). One can see that an initial concentration of 2E8 cells/mL completely removes the DCA with a concentration 1mM in (roughly) 150mins.

The Rate at which the intracellular concentration of the metabolites change over time:

Graph 2: Each line represents the concentration of each of the metabolites . This graph is simply a rescaling of graph 1. Note: the glycolate won’t accumulate in the cell – it is metabolised – the model had glycolate as the final product. It is used to show that the presence of glycolate can attribute to cell growth.

Rescaling the graph once again: the rate at which the metabolic intermediate change over time.

Graph 3: Each line represents the concentration of each of the metabolites . This graph is simply a rescaling of graph 1 and 2.

The rate at which the cells grow over time:

Graph 4: the blue line represents the linear increase of cells due to the presence of intracellular glycolate.

The Monooxygenase Pathway

ODE overview:

Raw MATLAB code:

function dy = p450(t,y)
 
dy=zeros(6,1);
 
dy(1)= -y(6)*(6*10^(-12))*0.0463067*(y(1)-y(2));
dy(2)= ((6*10^(-12))*0.0463067*(y(1)-y(2))) - 0.0113*25.55*(y(2)/(.12+y(2)));
dy(3) = 0.0113*25.55*(y(2)/(.12+y(2))) - 0.6*25.55*(y(3)/(0.16+y(3)));
dy(4)= 0.6*25.55*(y(3)/(0.16+y(3))) - 25.4*25.55*(y(4)/(20+y(4)));
 
 
   if y(5) >  2*10^(-10)
      dy(5)= 25.4*25.55*(y(4)/(20+y(4))) -1.5789*10^(-10)
   else
       dy(5) = 25.4*25.55*(y(4)/(20+y(4)))
   end
   
   if y(5) > 0.0005 
        if y(6) > 1.6*10^11
            dy(6)=0
        else
            dy(6) = 5*10^6
        end
   else
        dy(6) = 0
   end
 
end

MATLAB output:

The rate at which DCA is removed in solution:

Graph 5: The blue line represents how the concentration of DCA in solution (extracellular) decreases due to the action of our DCA degraders.

The Rate at which the intracellular concentration of the metabolites change over time:

Graph 6: Each line represents the intracellular concentration of each of the metabolites over time within a single cell. The colour associated with each metabolite is depicted in the figure legend. This graph is simply a rescaling of graph 5.

Rescaling the graph once again: the rate at which the metabolic intermediate change over time.

Graph 7: Again, each line represents the intracellular concentration of each of the metabolites over time within a single cell. This graph is simply a rescaling of graph 5 and 6.

The rate at which the cells grow over time:

Graph 8: The blue line represents the linear increase of the total number of cells due to the presence of intracellular glycolate.

Rescaling Shows a lag effect on cell growth:

Graph 9: The blue line represents the increase of cells due to the presence of intracellular glycolate. This graph is a rescaling of graph 8 to show the inital lag in cellualr growth.

With thanks to: